Integrand size = 33, antiderivative size = 610 \[ \int \frac {(g \cos (e+f x))^{5/2} \sin ^3(e+f x)}{a+b \sin (e+f x)} \, dx=-\frac {a^3 \left (-a^2+b^2\right )^{3/4} g^{5/2} \arctan \left (\frac {\sqrt {b} \sqrt {g \cos (e+f x)}}{\sqrt [4]{-a^2+b^2} \sqrt {g}}\right )}{b^{11/2} f}+\frac {a^3 \left (-a^2+b^2\right )^{3/4} g^{5/2} \text {arctanh}\left (\frac {\sqrt {b} \sqrt {g \cos (e+f x)}}{\sqrt [4]{-a^2+b^2} \sqrt {g}}\right )}{b^{11/2} f}-\frac {2 a^3 g (g \cos (e+f x))^{3/2}}{3 b^4 f}+\frac {2 a (g \cos (e+f x))^{7/2}}{7 b^2 f g}-\frac {2 a^4 g^2 \sqrt {g \cos (e+f x)} E\left (\left .\frac {1}{2} (e+f x)\right |2\right )}{b^5 f \sqrt {\cos (e+f x)}}+\frac {6 a^2 g^2 \sqrt {g \cos (e+f x)} E\left (\left .\frac {1}{2} (e+f x)\right |2\right )}{5 b^3 f \sqrt {\cos (e+f x)}}+\frac {4 g^2 \sqrt {g \cos (e+f x)} E\left (\left .\frac {1}{2} (e+f x)\right |2\right )}{15 b f \sqrt {\cos (e+f x)}}+\frac {a^4 \left (a^2-b^2\right ) g^3 \sqrt {\cos (e+f x)} \operatorname {EllipticPi}\left (\frac {2 b}{b-\sqrt {-a^2+b^2}},\frac {1}{2} (e+f x),2\right )}{b^6 \left (b-\sqrt {-a^2+b^2}\right ) f \sqrt {g \cos (e+f x)}}+\frac {a^4 \left (a^2-b^2\right ) g^3 \sqrt {\cos (e+f x)} \operatorname {EllipticPi}\left (\frac {2 b}{b+\sqrt {-a^2+b^2}},\frac {1}{2} (e+f x),2\right )}{b^6 \left (b+\sqrt {-a^2+b^2}\right ) f \sqrt {g \cos (e+f x)}}+\frac {2 a^2 g (g \cos (e+f x))^{3/2} \sin (e+f x)}{5 b^3 f}+\frac {4 g (g \cos (e+f x))^{3/2} \sin (e+f x)}{45 b f}-\frac {2 (g \cos (e+f x))^{7/2} \sin (e+f x)}{9 b f g} \]
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Time = 0.97 (sec) , antiderivative size = 610, normalized size of antiderivative = 1.00, number of steps used = 24, number of rules used = 16, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.485, Rules used = {2977, 2715, 2721, 2719, 2645, 30, 2648, 2774, 2946, 2780, 2886, 2884, 335, 304, 211, 214} \[ \int \frac {(g \cos (e+f x))^{5/2} \sin ^3(e+f x)}{a+b \sin (e+f x)} \, dx=-\frac {2 a^4 g^2 E\left (\left .\frac {1}{2} (e+f x)\right |2\right ) \sqrt {g \cos (e+f x)}}{b^5 f \sqrt {\cos (e+f x)}}-\frac {2 a^3 g (g \cos (e+f x))^{3/2}}{3 b^4 f}+\frac {6 a^2 g^2 E\left (\left .\frac {1}{2} (e+f x)\right |2\right ) \sqrt {g \cos (e+f x)}}{5 b^3 f \sqrt {\cos (e+f x)}}+\frac {2 a^2 g \sin (e+f x) (g \cos (e+f x))^{3/2}}{5 b^3 f}+\frac {a^4 g^3 \left (a^2-b^2\right ) \sqrt {\cos (e+f x)} \operatorname {EllipticPi}\left (\frac {2 b}{b-\sqrt {b^2-a^2}},\frac {1}{2} (e+f x),2\right )}{b^6 f \left (b-\sqrt {b^2-a^2}\right ) \sqrt {g \cos (e+f x)}}+\frac {a^4 g^3 \left (a^2-b^2\right ) \sqrt {\cos (e+f x)} \operatorname {EllipticPi}\left (\frac {2 b}{b+\sqrt {b^2-a^2}},\frac {1}{2} (e+f x),2\right )}{b^6 f \left (\sqrt {b^2-a^2}+b\right ) \sqrt {g \cos (e+f x)}}-\frac {a^3 g^{5/2} \left (b^2-a^2\right )^{3/4} \arctan \left (\frac {\sqrt {b} \sqrt {g \cos (e+f x)}}{\sqrt {g} \sqrt [4]{b^2-a^2}}\right )}{b^{11/2} f}+\frac {a^3 g^{5/2} \left (b^2-a^2\right )^{3/4} \text {arctanh}\left (\frac {\sqrt {b} \sqrt {g \cos (e+f x)}}{\sqrt {g} \sqrt [4]{b^2-a^2}}\right )}{b^{11/2} f}+\frac {2 a (g \cos (e+f x))^{7/2}}{7 b^2 f g}+\frac {4 g^2 E\left (\left .\frac {1}{2} (e+f x)\right |2\right ) \sqrt {g \cos (e+f x)}}{15 b f \sqrt {\cos (e+f x)}}-\frac {2 \sin (e+f x) (g \cos (e+f x))^{7/2}}{9 b f g}+\frac {4 g \sin (e+f x) (g \cos (e+f x))^{3/2}}{45 b f} \]
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Rule 30
Rule 211
Rule 214
Rule 304
Rule 335
Rule 2645
Rule 2648
Rule 2715
Rule 2719
Rule 2721
Rule 2774
Rule 2780
Rule 2884
Rule 2886
Rule 2946
Rule 2977
Rubi steps \begin{align*} \text {integral}& = \int \left (\frac {a^2 (g \cos (e+f x))^{5/2}}{b^3}-\frac {a (g \cos (e+f x))^{5/2} \sin (e+f x)}{b^2}+\frac {(g \cos (e+f x))^{5/2} \sin ^2(e+f x)}{b}-\frac {a^3 (g \cos (e+f x))^{5/2}}{b^3 (a+b \sin (e+f x))}\right ) \, dx \\ & = \frac {a^2 \int (g \cos (e+f x))^{5/2} \, dx}{b^3}-\frac {a^3 \int \frac {(g \cos (e+f x))^{5/2}}{a+b \sin (e+f x)} \, dx}{b^3}-\frac {a \int (g \cos (e+f x))^{5/2} \sin (e+f x) \, dx}{b^2}+\frac {\int (g \cos (e+f x))^{5/2} \sin ^2(e+f x) \, dx}{b} \\ & = -\frac {2 a^3 g (g \cos (e+f x))^{3/2}}{3 b^4 f}+\frac {2 a^2 g (g \cos (e+f x))^{3/2} \sin (e+f x)}{5 b^3 f}-\frac {2 (g \cos (e+f x))^{7/2} \sin (e+f x)}{9 b f g}+\frac {2 \int (g \cos (e+f x))^{5/2} \, dx}{9 b}+\frac {a \text {Subst}\left (\int x^{5/2} \, dx,x,g \cos (e+f x)\right )}{b^2 f g}-\frac {\left (a^3 g^2\right ) \int \frac {\sqrt {g \cos (e+f x)} (b+a \sin (e+f x))}{a+b \sin (e+f x)} \, dx}{b^4}+\frac {\left (3 a^2 g^2\right ) \int \sqrt {g \cos (e+f x)} \, dx}{5 b^3} \\ & = -\frac {2 a^3 g (g \cos (e+f x))^{3/2}}{3 b^4 f}+\frac {2 a (g \cos (e+f x))^{7/2}}{7 b^2 f g}+\frac {2 a^2 g (g \cos (e+f x))^{3/2} \sin (e+f x)}{5 b^3 f}+\frac {4 g (g \cos (e+f x))^{3/2} \sin (e+f x)}{45 b f}-\frac {2 (g \cos (e+f x))^{7/2} \sin (e+f x)}{9 b f g}-\frac {\left (a^4 g^2\right ) \int \sqrt {g \cos (e+f x)} \, dx}{b^5}+\frac {\left (2 g^2\right ) \int \sqrt {g \cos (e+f x)} \, dx}{15 b}+\frac {\left (a^3 \left (a^2-b^2\right ) g^2\right ) \int \frac {\sqrt {g \cos (e+f x)}}{a+b \sin (e+f x)} \, dx}{b^5}+\frac {\left (3 a^2 g^2 \sqrt {g \cos (e+f x)}\right ) \int \sqrt {\cos (e+f x)} \, dx}{5 b^3 \sqrt {\cos (e+f x)}} \\ & = -\frac {2 a^3 g (g \cos (e+f x))^{3/2}}{3 b^4 f}+\frac {2 a (g \cos (e+f x))^{7/2}}{7 b^2 f g}+\frac {6 a^2 g^2 \sqrt {g \cos (e+f x)} E\left (\left .\frac {1}{2} (e+f x)\right |2\right )}{5 b^3 f \sqrt {\cos (e+f x)}}+\frac {2 a^2 g (g \cos (e+f x))^{3/2} \sin (e+f x)}{5 b^3 f}+\frac {4 g (g \cos (e+f x))^{3/2} \sin (e+f x)}{45 b f}-\frac {2 (g \cos (e+f x))^{7/2} \sin (e+f x)}{9 b f g}-\frac {\left (a^4 \left (a^2-b^2\right ) g^3\right ) \int \frac {1}{\sqrt {g \cos (e+f x)} \left (\sqrt {-a^2+b^2}-b \cos (e+f x)\right )} \, dx}{2 b^6}+\frac {\left (a^4 \left (a^2-b^2\right ) g^3\right ) \int \frac {1}{\sqrt {g \cos (e+f x)} \left (\sqrt {-a^2+b^2}+b \cos (e+f x)\right )} \, dx}{2 b^6}+\frac {\left (a^3 \left (a^2-b^2\right ) g^3\right ) \text {Subst}\left (\int \frac {\sqrt {x}}{\left (a^2-b^2\right ) g^2+b^2 x^2} \, dx,x,g \cos (e+f x)\right )}{b^4 f}-\frac {\left (a^4 g^2 \sqrt {g \cos (e+f x)}\right ) \int \sqrt {\cos (e+f x)} \, dx}{b^5 \sqrt {\cos (e+f x)}}+\frac {\left (2 g^2 \sqrt {g \cos (e+f x)}\right ) \int \sqrt {\cos (e+f x)} \, dx}{15 b \sqrt {\cos (e+f x)}} \\ & = -\frac {2 a^3 g (g \cos (e+f x))^{3/2}}{3 b^4 f}+\frac {2 a (g \cos (e+f x))^{7/2}}{7 b^2 f g}-\frac {2 a^4 g^2 \sqrt {g \cos (e+f x)} E\left (\left .\frac {1}{2} (e+f x)\right |2\right )}{b^5 f \sqrt {\cos (e+f x)}}+\frac {6 a^2 g^2 \sqrt {g \cos (e+f x)} E\left (\left .\frac {1}{2} (e+f x)\right |2\right )}{5 b^3 f \sqrt {\cos (e+f x)}}+\frac {4 g^2 \sqrt {g \cos (e+f x)} E\left (\left .\frac {1}{2} (e+f x)\right |2\right )}{15 b f \sqrt {\cos (e+f x)}}+\frac {2 a^2 g (g \cos (e+f x))^{3/2} \sin (e+f x)}{5 b^3 f}+\frac {4 g (g \cos (e+f x))^{3/2} \sin (e+f x)}{45 b f}-\frac {2 (g \cos (e+f x))^{7/2} \sin (e+f x)}{9 b f g}+\frac {\left (2 a^3 \left (a^2-b^2\right ) g^3\right ) \text {Subst}\left (\int \frac {x^2}{\left (a^2-b^2\right ) g^2+b^2 x^4} \, dx,x,\sqrt {g \cos (e+f x)}\right )}{b^4 f}-\frac {\left (a^4 \left (a^2-b^2\right ) g^3 \sqrt {\cos (e+f x)}\right ) \int \frac {1}{\sqrt {\cos (e+f x)} \left (\sqrt {-a^2+b^2}-b \cos (e+f x)\right )} \, dx}{2 b^6 \sqrt {g \cos (e+f x)}}+\frac {\left (a^4 \left (a^2-b^2\right ) g^3 \sqrt {\cos (e+f x)}\right ) \int \frac {1}{\sqrt {\cos (e+f x)} \left (\sqrt {-a^2+b^2}+b \cos (e+f x)\right )} \, dx}{2 b^6 \sqrt {g \cos (e+f x)}} \\ & = -\frac {2 a^3 g (g \cos (e+f x))^{3/2}}{3 b^4 f}+\frac {2 a (g \cos (e+f x))^{7/2}}{7 b^2 f g}-\frac {2 a^4 g^2 \sqrt {g \cos (e+f x)} E\left (\left .\frac {1}{2} (e+f x)\right |2\right )}{b^5 f \sqrt {\cos (e+f x)}}+\frac {6 a^2 g^2 \sqrt {g \cos (e+f x)} E\left (\left .\frac {1}{2} (e+f x)\right |2\right )}{5 b^3 f \sqrt {\cos (e+f x)}}+\frac {4 g^2 \sqrt {g \cos (e+f x)} E\left (\left .\frac {1}{2} (e+f x)\right |2\right )}{15 b f \sqrt {\cos (e+f x)}}+\frac {a^4 \left (a^2-b^2\right ) g^3 \sqrt {\cos (e+f x)} \operatorname {EllipticPi}\left (\frac {2 b}{b-\sqrt {-a^2+b^2}},\frac {1}{2} (e+f x),2\right )}{b^6 \left (b-\sqrt {-a^2+b^2}\right ) f \sqrt {g \cos (e+f x)}}+\frac {a^4 \left (a^2-b^2\right ) g^3 \sqrt {\cos (e+f x)} \operatorname {EllipticPi}\left (\frac {2 b}{b+\sqrt {-a^2+b^2}},\frac {1}{2} (e+f x),2\right )}{b^6 \left (b+\sqrt {-a^2+b^2}\right ) f \sqrt {g \cos (e+f x)}}+\frac {2 a^2 g (g \cos (e+f x))^{3/2} \sin (e+f x)}{5 b^3 f}+\frac {4 g (g \cos (e+f x))^{3/2} \sin (e+f x)}{45 b f}-\frac {2 (g \cos (e+f x))^{7/2} \sin (e+f x)}{9 b f g}-\frac {\left (a^3 \left (a^2-b^2\right ) g^3\right ) \text {Subst}\left (\int \frac {1}{\sqrt {-a^2+b^2} g-b x^2} \, dx,x,\sqrt {g \cos (e+f x)}\right )}{b^5 f}+\frac {\left (a^3 \left (a^2-b^2\right ) g^3\right ) \text {Subst}\left (\int \frac {1}{\sqrt {-a^2+b^2} g+b x^2} \, dx,x,\sqrt {g \cos (e+f x)}\right )}{b^5 f} \\ & = -\frac {a^3 \left (-a^2+b^2\right )^{3/4} g^{5/2} \arctan \left (\frac {\sqrt {b} \sqrt {g \cos (e+f x)}}{\sqrt [4]{-a^2+b^2} \sqrt {g}}\right )}{b^{11/2} f}+\frac {a^3 \left (-a^2+b^2\right )^{3/4} g^{5/2} \text {arctanh}\left (\frac {\sqrt {b} \sqrt {g \cos (e+f x)}}{\sqrt [4]{-a^2+b^2} \sqrt {g}}\right )}{b^{11/2} f}-\frac {2 a^3 g (g \cos (e+f x))^{3/2}}{3 b^4 f}+\frac {2 a (g \cos (e+f x))^{7/2}}{7 b^2 f g}-\frac {2 a^4 g^2 \sqrt {g \cos (e+f x)} E\left (\left .\frac {1}{2} (e+f x)\right |2\right )}{b^5 f \sqrt {\cos (e+f x)}}+\frac {6 a^2 g^2 \sqrt {g \cos (e+f x)} E\left (\left .\frac {1}{2} (e+f x)\right |2\right )}{5 b^3 f \sqrt {\cos (e+f x)}}+\frac {4 g^2 \sqrt {g \cos (e+f x)} E\left (\left .\frac {1}{2} (e+f x)\right |2\right )}{15 b f \sqrt {\cos (e+f x)}}+\frac {a^4 \left (a^2-b^2\right ) g^3 \sqrt {\cos (e+f x)} \operatorname {EllipticPi}\left (\frac {2 b}{b-\sqrt {-a^2+b^2}},\frac {1}{2} (e+f x),2\right )}{b^6 \left (b-\sqrt {-a^2+b^2}\right ) f \sqrt {g \cos (e+f x)}}+\frac {a^4 \left (a^2-b^2\right ) g^3 \sqrt {\cos (e+f x)} \operatorname {EllipticPi}\left (\frac {2 b}{b+\sqrt {-a^2+b^2}},\frac {1}{2} (e+f x),2\right )}{b^6 \left (b+\sqrt {-a^2+b^2}\right ) f \sqrt {g \cos (e+f x)}}+\frac {2 a^2 g (g \cos (e+f x))^{3/2} \sin (e+f x)}{5 b^3 f}+\frac {4 g (g \cos (e+f x))^{3/2} \sin (e+f x)}{45 b f}-\frac {2 (g \cos (e+f x))^{7/2} \sin (e+f x)}{9 b f g} \\ \end{align*}
Result contains higher order function than in optimal. Order 6 vs. order 4 in optimal.
Time = 19.23 (sec) , antiderivative size = 790, normalized size of antiderivative = 1.30 \[ \int \frac {(g \cos (e+f x))^{5/2} \sin ^3(e+f x)}{a+b \sin (e+f x)} \, dx=\frac {(g \cos (e+f x))^{5/2} \left (\frac {\sin (e+f x) \left (-\frac {\left (15 a^4-9 a^2 b^2-2 b^4\right ) \csc (e+f x) \left (8 b^{5/2} \operatorname {AppellF1}\left (\frac {3}{4},-\frac {1}{2},1,\frac {7}{4},\cos ^2(e+f x),\frac {b^2 \cos ^2(e+f x)}{-a^2+b^2}\right ) \cos ^{\frac {3}{2}}(e+f x)+3 \sqrt {2} a \left (a^2-b^2\right )^{3/4} \left (2 \arctan \left (1-\frac {\sqrt {2} \sqrt {b} \sqrt {\cos (e+f x)}}{\sqrt [4]{a^2-b^2}}\right )-2 \arctan \left (1+\frac {\sqrt {2} \sqrt {b} \sqrt {\cos (e+f x)}}{\sqrt [4]{a^2-b^2}}\right )-\log \left (\sqrt {a^2-b^2}-\sqrt {2} \sqrt {b} \sqrt [4]{a^2-b^2} \sqrt {\cos (e+f x)}+b \cos (e+f x)\right )+\log \left (\sqrt {a^2-b^2}+\sqrt {2} \sqrt {b} \sqrt [4]{a^2-b^2} \sqrt {\cos (e+f x)}+b \cos (e+f x)\right )\right )\right )}{a^2-b^2}+\frac {(2+2 i) b^2 \left (-3 a^3+a b^2\right ) \left ((4-4 i) a \sqrt {b} \sqrt [4]{-a^2+b^2} \operatorname {AppellF1}\left (\frac {3}{4},\frac {1}{2},1,\frac {7}{4},\cos ^2(e+f x),\frac {b^2 \cos ^2(e+f x)}{-a^2+b^2}\right ) \cos ^{\frac {3}{2}}(e+f x)+3 \left (a^2-b^2\right ) \left (2 \arctan \left (1-\frac {(1+i) \sqrt {b} \sqrt {\cos (e+f x)}}{\sqrt [4]{-a^2+b^2}}\right )-2 \arctan \left (1+\frac {(1+i) \sqrt {b} \sqrt {\cos (e+f x)}}{\sqrt [4]{-a^2+b^2}}\right )-\log \left (\sqrt {-a^2+b^2}-(1+i) \sqrt {b} \sqrt [4]{-a^2+b^2} \sqrt {\cos (e+f x)}+i b \cos (e+f x)\right )+\log \left (\sqrt {-a^2+b^2}+(1+i) \sqrt {b} \sqrt [4]{-a^2+b^2} \sqrt {\cos (e+f x)}+i b \cos (e+f x)\right )\right )\right )}{\left (-a^2+b^2\right )^{5/4} \sqrt {\sin ^2(e+f x)}}\right ) \left (a+b \sqrt {\sin ^2(e+f x)}\right )}{12 b^{11/2} (a+b \sin (e+f x))}+\frac {\cos ^{\frac {3}{2}}(e+f x) \left (90 a b^2 \cos (2 (e+f x))+21 b \left (12 a^2+b^2\right ) \sin (e+f x)-5 \left (84 a^3-18 a b^2+7 b^3 \sin (3 (e+f x))\right )\right )}{42 b^4}\right )}{15 f \cos ^{\frac {5}{2}}(e+f x)} \]
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Result contains higher order function than in optimal. Order 9 vs. order 4.
Time = 24.72 (sec) , antiderivative size = 2001, normalized size of antiderivative = 3.28
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Timed out. \[ \int \frac {(g \cos (e+f x))^{5/2} \sin ^3(e+f x)}{a+b \sin (e+f x)} \, dx=\text {Timed out} \]
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Timed out. \[ \int \frac {(g \cos (e+f x))^{5/2} \sin ^3(e+f x)}{a+b \sin (e+f x)} \, dx=\text {Timed out} \]
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\[ \int \frac {(g \cos (e+f x))^{5/2} \sin ^3(e+f x)}{a+b \sin (e+f x)} \, dx=\int { \frac {\left (g \cos \left (f x + e\right )\right )^{\frac {5}{2}} \sin \left (f x + e\right )^{3}}{b \sin \left (f x + e\right ) + a} \,d x } \]
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\[ \int \frac {(g \cos (e+f x))^{5/2} \sin ^3(e+f x)}{a+b \sin (e+f x)} \, dx=\int { \frac {\left (g \cos \left (f x + e\right )\right )^{\frac {5}{2}} \sin \left (f x + e\right )^{3}}{b \sin \left (f x + e\right ) + a} \,d x } \]
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Timed out. \[ \int \frac {(g \cos (e+f x))^{5/2} \sin ^3(e+f x)}{a+b \sin (e+f x)} \, dx=\int \frac {{\sin \left (e+f\,x\right )}^3\,{\left (g\,\cos \left (e+f\,x\right )\right )}^{5/2}}{a+b\,\sin \left (e+f\,x\right )} \,d x \]
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